SOWER’S SEVENS IN THE 7TH CENTURY

 

 

 

SOWER’ SEVENS IN THE 7TH CENTURY

Sower’s Sevens are in the Κoran, compiled in the 7th century.

Sower’s Sevens are also in the Hebrew Bible, in the New Testament, in the Samaritan Pentateuch, and in the Syriac Aseneth. I have found 14 examples of Sower’s Sevens in these other books and 5 examples in the Κoran.

What are Sower’s Sevens? This is a number pattern that emerges from these sacred texts when number sets are manipulated with the numbers given in the Sower’s Parables in the Gospel, that is, 30, 60, 100 and/or 100, 60, 30.

What emerges is a factor of 70 x 7.

Seven is a favored number in the Bible. The biblical “70 x 7” is found (printed, not hidden) in Matthew 18:22 (footnote NRSV) and also in Genesis 4:24.  By the way, I believe that means seventy times sevenfold (DRA), not 77 times.

The Sower’s Parables numbers can be found at: (1) Matthew 13:8 (100, 60, 30); (2) Matthew 13:23 (100, 60, 30); (3) Mark 4:8 (30, 60, 100); (4) Mark 4:20 (30, 60, 100); and (5) Luke 8:8 (100).

Is it a surprise to find the same number pattern in all these different sacred texts? Not really surprising when you consider they all share commonality of expression; for example, the Κoran, the Hebrew Bible, and the New Testament all mention Moses and Abraham.

I am accustomed to saying “Sower’s Sevens.” Do scholars of Ιslam know about Sower’s Sevens? What do they call the sevens?

I am definitely not qualified to interpret the Κoran for you as I have not even finished reading it; however, I believe I can speak authoritatively about the presence of a certain number pattern (a factor of 70 x 7). Mathematics is universal and anyone who has had some schooling should be able to understand this post and do the simple arithmetic (add, multiply, divide), which is the math in this post with the exception of a few exponents which is high school math.

As far as I know, the Sower’s Sevens are not in the words of the Κoran, but rather appear in the “stray mark letters” at the beginning of some chapters, and appear when you consider the number of verses in each chapter, and also the number of chapters.

The Sower’s Sevens puzzles in the Κoran are quite sophisticated in terms of at least one result (a 70 x 70) and the presence of multiple Sower’s Sevens puzzles in the same number set.

The care that has been given to preserving the Κoran over the centuries, so that it has not been subject to editing, is evident to me, and I am grateful for this careful preservation as it allows me to find the Sower’s Sevens puzzles. Alteration of the original might have ruined the puzzles.

I call them puzzles, but of course I do not know the purpose of the Sower’s Sevens. Perhaps it is to give praise to the Creator of all. See my post on the wonders of the numbers in the so-called Pascal’s Triangle, and how the 70 x 7 may be related to all that.

I do not agree that the numbers in sacred texts are necessarily “numerology,” that is, according to the dictionary definition, a practice that assigns occult meaning to numbers, but rather, I would like to presume the ancients had knowledge of real math.

Below I have 5 examples of solutions to number sets in the Κoran which yield a 70 x 7, which brings the total number of examples I have gathered to 19. Now with this 19th instance of my discovering a “seventy times seven” with Sower’s Parables numbers (see links in sidebar for other examples), I have to ask, what are the odds against gaining nineteen instances of “seventy times seven”? We can readily see that the odds of a factor of 7 x 7 are 1 in 49. The probability against nineteen instances of 49 is 1 in 49 to the 19th power, in other words, astronomical!!! The presence of 70 x 7 in sacred texts is very likely not random.

I used an English version of the Κoran by MM Pickthall which is available at sacred-texts.com. I don’t know how accurate that version is relative to other versions. No translation can fully capture the meaning of the words in the original Αrabic.

 

SOLUTION 1 – 114 chapters

I will start with the simplest Solution first. This will give you a clue how to use the Sower’s Parable numbers to reveal 70 x 7:

There are 114 chapters in the book. This means 1 of a hundred, 1 of ten, and 4 of units.

Take the values 1, 1, 4:

Multiply by the Sower’s Parable numbers 30, 60, 100:

1 x 30 = 30

1 x 60 = 60

4 x 100 = 400

Sum of products = 490 = 70 x 7

 

SOLUTION 2 – the stray marks

For each chapter, I give the chapter number, the stray mark letters written phonetically, and the numerical value of each stray mark letter. There are 78 values. These can be divided into three equal parts of 26 values each and subtotaled as shown:

2, Alif Lam Mim, 1 30 40

3, Alif Lam Mim, 1 30 40

7, Alif Lam Mim Sad, 1 30 40 90

10, Alif Lam Ra, 1 30 200

11, Alif Lam Ra, 1 30 200

12, Alif Lam Ra, 1 30 200

13, Alif Lam Mim Ra, 1 30 40 200

14, Alif Lam Ra, 1 30 200

Subtotal = 1,498

15, Alif Lam Ra, 1 30 200

19, Kaf Ha Ya A’in Sad, 20 5 10 70 90

20, Ta Ha, 9 5

26, Ta Sin Mim, 9 60 40

27, Ta Sin, 9 60

28, Ta Sin Mim, 9 60 40

29, Alif Lam Mim, 1 30 40

30, Alif Lam Mim, 1 30 40

31, Alif Lam, 1 30

Subtotal = 900

31 continued, Mim, 40

32, Alif Lam Mim, 1 30 40

36, Ya Sin, 10 60

38, Sad, 90

40, Ha Mim, 5 40

41, Ha Mim, 5 40

42, verse 1, Ha Mim, 5 40

42, verse 2, A’in Sin Qaf, 20 60 100

43, Ha Mim, 5 40

44, Ha Mim, 5 40

45, Ha Mim, 5 40

46, Ha Mim, 5 40

50, Qaf, 100

68, Nun, 50

Subtotal = 916

Now I multiply each subtotal by the Sower’s Parable numbers 100, 60, 30

1,498 x 100 = 149,800

900 x 60 = 54,000

916 x 30 = 27, 480

Sum of products = 231,280 and a factor is 70 x 7

I notice that 231,280/70 = 3,304, which is the sum of values in the first triangle with 7-factors in the so-called Pascal’s Triangle (7 + 21 + 35 + 35 + 21 + 7 + 28 + 56 + 70 + 56 + 28 + 84 + 126 + 126 + 84 + 210 + 252 + 210 + 462 + 462 + 924 = 3,304).

When I do the reverse and multiply by the Sower’s Parable numbers 30, 60, 100, I get a factor of 70 as expected, but the sum of products also yields the factor 2,722, which is the sum of the 54 odd values for number of verses per chapter (see next Solution for a list of the 60 even values and 54 odd values)

1,498 x 30 = 44, 940

900 x 60 = 54,000

916 x 100 = 91,600

Sum of products = 190, 540 and factors are 70 and 2,722

In this Solution 2 which addresses the stray mark letters which occur at the beginnings of 29 chapters, I readily admit that I am not able to distinguish between some letters to determine the numerical value, as I am not familiar with the alphabet for this language. However, with careful work and some guessing, it would seem that I have done it correctly, as I have arrived at a spectacular answer above, a factor of 70 x 7.

 

SOLUTION 3 – the odd and the even

This Solution and the next two use the following values. What follows is a list showing the total number of verses in each of the 114 chapters in the book. Some verse totals are even (a multiple of 2), some are odd (that is, not even). There are 60 even verse totals and 54 odd verse totals.

1-7, 2-286, 3-200, 4-176, 5-120, 6-165, 7-206, 8-75, 9-129, 10-109, 11-123, 12-111, 13-43, 14-52, 15-99, 16-128, 17-111, 18-110, 19-98, 20-135, 21-112, 22-78, 23-118, 24-64, 25-77, 26-227, 27-93, 28-88, 29-69, 30-60, 31-34, 32-30, 33-73, 34-54, 35-45, 36-83, 37-182, 38-88, 39-75, 40-85, 41-54, 42-53, 43-89, 44-59, 45-37, 46-35, 47-38, 48-29, 49-18, 50-45, 51-60, 52-49, 53-62, 54-55, 55-78, 56-96, 57-29, 58-22, 59-24, 60-13, 61-14, 62-11, 63-11, 64-18, 65-12, 66-12, 67-30, 68-52, 69-52, 70-44, 71-28, 72-28, 73-20, 74-56, 75-40, 76-31, 77-50, 78-40, 79-46, 80-42, 81-29, 82-19, 83-36, 84-25, 85-22, 86-17, 87-19, 88-26, 89-30, 90-20, 91-15, 92-21, 93-11, 94-8, 95-8, 96-19, 97-5, 98-8, 99-8, 100-11, 101-11, 102-8, 103-3, 104-9, 105-5, 106-4, 107-7, 108-3, 109-6, 110-3, 111-5, 112-4, 113-5, 114-6.

I start with the first value which is 7, an odd number. The next value I pick is the next even number, 286. The next value I pick is the next odd number, 165. The next value I pick is the next even number, 206, and so on, odd, even, odd, even, until I reach the end. This number set contains 60 values which I divide into 3 equal parts of 20 values each as follows:

7 286 165 206 75 52 99 128 111 110 135 112 77 88 69 60 73 54 45 182

Subtotal = 2,134

75 54 53 38 29 18 45 60 49 62 55 78 29 22 13 14 11 18 31 50

Subtotal = 804

29 36 25 22 17 26 15 8 19 8 11 8 3 4 7 6 3 4 5 6

Subtotal = 262

Interesting that the total is 3200 which contains 2^7, that is, 2 raised to the 7th power.

Next I multiply with the Sower’s Parable numbers, 100, 60, 30:

2,134 x 100 = 213,400

804 x 60 = 48,240

262 x 30 = 7,860

Sum of products = 269,500 with a factor of 70 x 70, yes, 70 squared !!!

Of course the sum of products contains the factor 70 x 7 also.

I did all that with odd/even numbers and then I noticed 89:3, “And the Even and the Odd,” but what does that verse mean?

 

SOLUTION 4 – corresponding chapter numbers

The number set for this Solution is the 60 chapter numbers which correspond to the odd and even selection of verse totals in the previous Solution. The chapter numbers are in 3 equal parts of 20 values each:

1 2 6 7 8 14 15 16 17 18 20 21 25 28 29 30 33 34 35 37

Subtotal = 396

39 41 42 47 48 49 50 51 52 53 54 55 57 58 60 61 62 64 76 77

Subtotal = 1096

81 83 84 85 86 88 91 94 96 98 100 102 103 106 107 109 110 112 113 114

Subtotal = 1,962

Next I multiply with Sower’s parables numbers, 100, 60, 30 and then 30, 60, 100:

396 x 100 = 39,600

1096 x 60 = 65,760

1962 x 30 = 58,860

Sum of products = 164,220 with factors of 70 or 12

396 x 30 = 11,880

1096 x 60 = 65,760

1962 x 100 = 196,200

Sum of products = 273,840 with factors of 70 or 12

Combined sums of products = 164,220 + 273,840 = 438,060 with factor of 70 x 7

So amazing to get yet another factor of 70 x 7 from among the chapter and verse values.

 

SOLUTION 5 – bracketed numbers

I noticed subsets of numbers among the odd-even number set in Solution 3 that were bracketed by identical numbers. One of these subsets worked for me. It is a group of 15 values that is bracketed at each end by a 75. The central number is 77. Is a 77 prized as is a 70 x 7?

The 15 values are arranged here in 3 equal parts of 5 values each:

52 99 128 111 110

Subtotal = 500

135 112 77 88 69

Subtotal = 481

60 73 54 45 182

Subtotal = 414

Next I multiply with Sower’s Parable numbers, 30, 60, 100:

500 x 30 = 15,000

481 x 60 = 28,860

414 x 100 = 41,400

Sum of products = 85,260 with a factor of 70 x 7

 

 

 

 

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